Challenge Questions PPL Sec 1.
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Challenge Questions PPL Sec 1.
Q 1. The temperature at 8, 500ft is forecast to be ISA+15. What would you expect the actual temperature to be? Show working out.
Q 2. Convert 28° ,42' 4'' of Arc units, into time. Show working out.
Q 3. Describe the characteristics of a tropical cyclone in the mature stage of its life cycle. Refer to wind speeds, spiral bands, surface pressure and distances from the center of the eye.
Q 4. What are the conditions required for 'lower level jet streams'?
Q 5. What are FÖhn Winds?
Q 6. What does the term 'adiabatic' refer to?
Q 7. What is the formula for calculating a cloud base formed by convection?
Q 8. What constitutes the parameters of a line squall?
Q 9. What constitutes the parameters of a microburst?
Q 10. In degrees latitude, where are cyclones prone to evolve and over what temperatures? In degrees latitude where are cyclones prone to dissipate?
Q 11. From which measurement of the atmosphere can stability be determined?
Q 2. Convert 28° ,42' 4'' of Arc units, into time. Show working out.
Q 3. Describe the characteristics of a tropical cyclone in the mature stage of its life cycle. Refer to wind speeds, spiral bands, surface pressure and distances from the center of the eye.
Q 4. What are the conditions required for 'lower level jet streams'?
Q 5. What are FÖhn Winds?
Q 6. What does the term 'adiabatic' refer to?
Q 7. What is the formula for calculating a cloud base formed by convection?
Q 8. What constitutes the parameters of a line squall?
Q 9. What constitutes the parameters of a microburst?
Q 10. In degrees latitude, where are cyclones prone to evolve and over what temperatures? In degrees latitude where are cyclones prone to dissipate?
Q 11. From which measurement of the atmosphere can stability be determined?
Re: Challenge Questions PPL Sec 1.
Q1...according to ISA the temperature at 8500 should be -2 C .....this comes from that temperature decreases 2 degrees Celsius for every 1000 ft....
so from sea level to 8500 feet we have 17degrees difference....so +15 - 17= -2 C
Q2....1 hour 54 min 49 seconds
so from sea level to 8500 feet we have 17degrees difference....so +15 - 17= -2 C
Q2....1 hour 54 min 49 seconds
Kerveras Andreas- Posts : 13
Info Rating : 0
Join date : 2009-12-01
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